12x^2=-20x

Solution for 12x^2=-20x equation:

12x^2=-20x

We move all terms to the left:

12x^2-(-20x)=0

We get rid of parentheses

12x^2+20x=0

a = 12; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·12·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*12}=\frac{-40}{24}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*12}=\frac{0}{24}
=0
$